Linear equations are those equations which are linear in its variables i.e. the power of the variables are 1. There can be many kinds of linear equations depending upon the number of variables used. a single variable linear equation has one variable, a double variable linear equation has two variables, a triple variable linear equation has three variables and so on. The linear equations with two or more variables is called a multi-variable linear equation. A single variable linear equation looks like this: ax = b where x is the variable. A double variable linear equation looks like this: ax + by = c and a triple variable linear equation looks like this: ax + by + cz = d. The number of variables can extend to any number of variables.
The solution of a linear requires as much equations as there are variables in it. A single variable linear equation requires one equation. a double variable linear equation requires two variables and a three variable linear equation requires three equations. The number of variables is equal to the number of equations. When we find the solution of a set of linear equations then the solutions can be unique or dependent or no solution. The solution of a linear equation can be found with the help of substitution, elimination or with the help of determinants. The solution using determinants is very cumbersome so to simplify the steps we use Gauss algorithms which use matrix to solve such equations. Let us look at the solutions of some linear equations.
Single variable linear equation
A single variable linear equation ax = b has solution x = b/a. When we plot it on a graph then we get a straight line parallel to y-axis. As the value of y is not present in the equation therefore the solution is independent of y.
Double variable linear equation
A double variable linear equation can be solved either by substitution method or elimination method. The solution on a graph is the point of intersection of the lines represented by the two equations.
The equations are 2x − y = 3 and 4x + y = −6
Let us solve the above two equations by substitution method and elimination method.
Substitution method
In substitution method we express one variable in terms of the other and substitute it to get value of one variable. Then substitute it in any equation to get value of other variable.
Step 1:Express any one equation in terms of one variable.
2x−y = 3 ⇒ y = 2x − 3
Step 2:Substitute it in next equation.
4x + y = −6
⇒ 4x + 2x − 3 = −6
⇒ 6x = −3
⇒ x = −(1/2) = −.5
Step 3:Substitute value in the first equation.
y = 2x − 3 = 2(−.5) − 3 = −4
So solution is x = −.5 and y = −4
Elimination method
The elimination method is based on the fact that if one variable is removed from the equation then the reduced equation contains only one variable. After we can find the solution. Substitute one solution in one equation to get the other solution.
Step 1: Eliminate one variable by making coefficient of that variable equal in two equations.
the linear equations of multi variables is found by Gauss elimination method. We will discuss about such methods in some other posts.
The solution of a linear requires as much equations as there are variables in it. A single variable linear equation requires one equation. a double variable linear equation requires two variables and a three variable linear equation requires three equations. The number of variables is equal to the number of equations. When we find the solution of a set of linear equations then the solutions can be unique or dependent or no solution. The solution of a linear equation can be found with the help of substitution, elimination or with the help of determinants. The solution using determinants is very cumbersome so to simplify the steps we use Gauss algorithms which use matrix to solve such equations. Let us look at the solutions of some linear equations.
Single variable linear equation
A single variable linear equation ax = b has solution x = b/a. When we plot it on a graph then we get a straight line parallel to y-axis. As the value of y is not present in the equation therefore the solution is independent of y.
Double variable linear equation
A double variable linear equation can be solved either by substitution method or elimination method. The solution on a graph is the point of intersection of the lines represented by the two equations.
The equations are 2x − y = 3 and 4x + y = −6
Let us solve the above two equations by substitution method and elimination method.
Substitution method
In substitution method we express one variable in terms of the other and substitute it to get value of one variable. Then substitute it in any equation to get value of other variable.
Step 1:Express any one equation in terms of one variable.
2x−y = 3 ⇒ y = 2x − 3
Step 2:Substitute it in next equation.
4x + y = −6
⇒ 4x + 2x − 3 = −6
⇒ 6x = −3
⇒ x = −(1/2) = −.5
Step 3:Substitute value in the first equation.
y = 2x − 3 = 2(−.5) − 3 = −4
So solution is x = −.5 and y = −4
Elimination method
The elimination method is based on the fact that if one variable is removed from the equation then the reduced equation contains only one variable. After we can find the solution. Substitute one solution in one equation to get the other solution.
Step 1: Eliminate one variable by making coefficient of that variable equal in two equations.
2x − y = 3
4x+ y = −6
Add the two equations
6x = −3
x = −(1/2) = −.5
Substitute in anyone
2(−.5) − y = 3
y = − 4
the linear equations of multi variables is found by Gauss elimination method. We will discuss about such methods in some other posts.
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